Bucket name must match the regex boto3
WebJul 22, 2024 · Lambda erreur Bucket name must match the regex. I am looking to copy a json stored in an S3 bucket and put it in DynamoDB. Here is the code for my lambda: import boto3 import json import ast s3_client = boto3.client ('s3') dynamodb_client = boto3.resource ('dynamodb') def lambda_handler (event, context): # First we will fetch … WebFeb 2, 2024 · Bucket name must match the regex "^ [a-zA-Z0-9. \-] {1,255}$" It works if I just do folder, but not if I try to do folder/subfolder1/subfolder2. I tried to understand it with the documentation but could not. Can someone please explain it to me? Thanks python amazon-web-services amazon-s3 boto3 Share Improve this question Follow
Bucket name must match the regex boto3
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WebJan 14, 2024 · As pointed out by @John Rotenstein , all bucket name must be DNS-compliant, so a direct slash is not allowed for bucket name. In fact the 2nd piece of code above does work, when I added this: for key in bucket.get_all_keys(prefix='s-DI-S/', delimiter='/') and took what was really the prefix off the Bucketname. WebApr 20, 2024 · bucket = s3.Bucket(bucket_name) bucket = object(bucket) for obj in bucket.objects.all(): I come across an error: Bucket name must match the regex "^[a …
WebThe exact path to match on. regex (string) – The regex used to match the path. port (integer) – The port number to match on. prefix (string) – Specifies the path to match requests with. This parameter must always start with /, which by itself matches all requests to the virtual service name. You can also match for path-based routing of ... WebMar 3, 2024 · Here is my code import boto3 s3 = boto3.resource ('s3') my_bucket = s3.Bucket ('my_project') for my_bucket_object in my_bucket.objects.all (): print (my_bucket_object.key) it works. I get all files' names. However, when I tried to do the same thing on a folder, the code raise an error
WebNov 26, 2024 · This is a regular expression error, you are getting this error because you are using the wrong syntax. Your statement should be as follows: C:\Users\jino>aws s3 ls s3://testdm/ This will work well. answered Nov 26, 2024 by Nabarupa Das 0 votes Instead of backslashes, use forward slashes C:\Users\jino>aws s3 ls s3://testdm WebJun 6, 2024 · Method 3: Via Boto using python import boto3 s3 = boto3.resource ('s3') copy_source = { 'Bucket': 'staging', 'Key': '/AwsTesting/research/' } s3.meta.client.copy (copy_source, 'staging', '/AwsTesting/research_archive/') With my understanding I have assumed the 'key' for bucket is just the folder prefix so I have mentioned the folder path …
WebApr 23, 2024 · Below is my working code. import boto3 import pandas as pd def get_s3_dataframe (object_name,schema): s3 = boto3.resource ('s3') s3_bucket = 'some-bucket' s3_prefix = f'/ {object_name}/data/' bucket = s3.Bucket (s3_bucket) s3_data = None for obj in bucket.objects.filter (Prefix=s3_prefix): //read-data return s3_data
WebAug 28, 2024 · import boto3 import botocore access_point_arn = "arn:aws:s3:region:account-id:accesspoint/resource" client = boto3.client ('s3') response = client.list_objects_v2 (Bucket=access_point_arn) Somehow getting the error below: ext_analiticoWebMar 2, 2024 · Are you trying to use s3 access point or s3 Outpost ARN ? These are the only ways to use bucket ARN with get_object api. … bucees biloxiWebAug 21, 2024 · Assuming countries.csv is the file in the S3 bucket and test.csv is the name of the file in which you want to download, s3.Bucket ('bucket-Name').download_file ('prod/daily-snapshot/2024/08/19/countries.csv', 'test.csv') The argument, Bucket requires the name of the bucket and the argument Key requires the full path (full key) inside the … bucees birthday invitationsWebFeb 21, 2024 · The bucket name can be between 3 and 63 characters long, and can contain only lower-case characters, numbers, periods, and dashes. Each label in the bucket name must start with a lowercase letter or number. The bucket name cannot contain underscores, end with a dash, have consecutive periods, or use dashes adjacent to … bucees birthday cakeWebAccording to [AmazonAWS.Boto3]: S3.Client - upload_fileobj ( Fileobj, Bucket, Key, ExtraArgs=None, Callback=None, Config=None), the 2 nd and 3 rd arguments ( Bucket and Key) must be strings. But you are passing as a 2 nd argument: bucket = s3.Bucket ('MY_URL') which is not OK. Make it a plain string (and even better, rename it): ext analytics also referred to as text miningWebSep 14, 2024 · 1 Answer Sorted by: 3 Bucket names can't have slashes. Thus in your case, sample must be part of the object's name, as it will be considered as s3 prefix: bucket_name = "waterbucket" object_name = "sample/file.json" Share Follow answered Sep 14, 2024 at 23:44 Marcin 203k 13 197 253 Add a comment Your Answer extand ciblexWebRegex (dict) – If specified, the configuration option must be a string value that satisfies this regular expression. Pattern (string) – The regular expression pattern that a string configuration option value with this restriction must match. Label (string) – A unique name representing this regular expression. Exceptions bucees best snacks